Question:

In the given figure, PA is the tangent drawn from an external point P to the circle with center O. If the radius of the circle is 3 cm and PA = 4 cm, then the length of PB is
A is the tangent drawn from an external point P

Updated On: Apr 4, 2025
  • 3 cm
  • 2 cm

  • 5 cm
  • 4 cm

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The Correct Option is D

Solution and Explanation

Given: PA is the tangent from an external point \( P \) to a circle with center \( O \). The radius of the circle is 3 cm, and the length of \( PA = 4 \) cm.

Step 1: Understanding the right-angled triangle 

Since \( PA \) is a tangent to the circle at point \( A \), the radius \( OA \) is perpendicular to the tangent \( PA \). This forms a right-angled triangle \( OPA \), where:

  • \( OP \) is the hypotenuse
  • \( OA = 3 \) cm (radius)
  • \( PA = 4 \) cm (tangent length)

Step 2: Applying the Pythagoras Theorem

\[ OP^2 = OA^2 + PA^2 \] \[ OP^2 = 3^2 + 4^2 \] \[ OP^2 = 9 + 16 = 25 \] \[ OP = \sqrt{25} = 5 \text{ cm} \]

Step 3: Finding PB

Since two tangents drawn from an external point to a circle are equal in length, we have:

\[ PB = PA = 4 \text{ cm} \]

Final Answer: 4 cm

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