2 cm
4 cm
Given: PA is the tangent from an external point \( P \) to a circle with center \( O \). The radius of the circle is 3 cm, and the length of \( PA = 4 \) cm.
Step 1: Understanding the right-angled triangle
Since \( PA \) is a tangent to the circle at point \( A \), the radius \( OA \) is perpendicular to the tangent \( PA \). This forms a right-angled triangle \( OPA \), where:
Step 2: Applying the Pythagoras Theorem
\[ OP^2 = OA^2 + PA^2 \] \[ OP^2 = 3^2 + 4^2 \] \[ OP^2 = 9 + 16 = 25 \] \[ OP = \sqrt{25} = 5 \text{ cm} \]
Step 3: Finding PB
Since two tangents drawn from an external point to a circle are equal in length, we have:
\[ PB = PA = 4 \text{ cm} \]
Final Answer: 4 cm