We are given that \( O \) is the centre of the circle and \( \angle AOC = 110^\circ \). In the case of a circle, the angle at the centre of the circle is twice the angle subtended at the circumference by the same chord. This means: \[ \angle AOC = 2 \times \angle ADC \] Substituting the given value of \( \angle AOC \): \[ 110^\circ = 2 \times \angle ADC \] Now, solving for \( \angle ADC \): \[ \angle ADC = \frac{110^\circ}{2} = 55^\circ \]
The correct option is (B): \(55°\)