The problem involves finding the probability that a randomly chosen point within the square falls inside the shaded area formed by the intersection of two circular sectors with radius equal to the side length of the square.
Step 1: Understand the geometry of the problem.
- Let the side of the square PQRS be \( r \).
- The shaded area is formed by the intersection of two sectors of circles, each with radius \( r \) and centers at \( S \) and \( Q \).
- The area of each sector is given by:
\[
A_{\text{sector}} = \frac{\theta}{360^\circ} \times \pi r^2
\]
where \( \theta \) is the central angle of the sector. In this case, \( \theta = 90^\circ \), so the area of each sector is:
\[
A_{\text{sector}} = \frac{90^\circ}{360^\circ} \times \pi r^2 = \frac{\pi r^2}{4}
\]
Step 2: Calculate the area of the shaded region.
- The shaded area is formed by the intersection of two such sectors. The total area of the sectors is \( \frac{\pi r^2}{2} \), but we need to subtract the area of the overlap between the two sectors, which is \( r^2 \). Hence, the area of the shaded region is:
\[
A_{\text{shaded}} = \frac{\pi r^2}{2} - r^2
\]
Step 3: Calculate the probability.
- The area of the square is \( r^2 \), so the probability that a randomly chosen point falls inside the shaded region is:
\[
\text{Probability} = \frac{A_{\text{shaded}}}{A_{\text{square}}} = \frac{\frac{\pi r^2}{2} - r^2}{r^2} = \frac{\pi}{2} - 1
\]
Thus, the correct answer is option (C).
Final Answer: \( \frac{\pi}{2} - 1 \)