Question:
In the estimation of sulphur by Carius method, $0.480\, g$ of an organic compound gives $0.699 \,g$ of barium sulphate. The percentage of sulphur in this compound is (Atomic masses: $Ba\, = 137, S = 32, 0 = 16)$
In the estimation of sulphur by Carius method, $0.480\, g$ of an organic compound gives $0.699 \,g$ of barium sulphate. The percentage of sulphur in this compound is (Atomic masses: $Ba\, = 137, S = 32, 0 = 16)$
Updated On: Mar 4, 2024
- 20%
- 15%
- 35%
- 30%
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The Correct Option is A
Solution and Explanation
$ S \% =\frac{32}{233} \times \frac{\text { wt. of BaSO }_{4}}{\text { wt. of organic compound }} \times 100 $
$=\frac{32}{233} \times \frac{0.699}{0.480} \times 100 $
$=20 \% $
$=\frac{32}{233} \times \frac{0.699}{0.480} \times 100 $
$=20 \% $
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