To determine the new water level when all objects are removed, follow these steps:
1. **Understand the Container Volume**: The container dimensions are 40 cm x 20 cm x 20 cm.
2. **Calculate the Total Container Volume**:
\[ \text{Volume} = 40 \, \text{cm} \times 20 \, \text{cm} \times 20 \, \text{cm} = 16000 \, \text{cm}^3 \]
3. **Calculate the Immersed Volume of Each Object**:
- **Object P**:
- P is a cube with an edge of 4 cm:
\[ \text{Cube Volume} = 4^3 = 64 \, \text{cm}^3 \]
- Since 1/10th is above water:
\[ \text{Immersed Volume (P)} = \left( \frac{9}{10} \right) \times 64 = 57.6 \, \text{cm}^3 \]
- **Object Q**:
- Displaces 50 cc of water when floating.
\[ \text{Immersed Volume (Q)} = 50 \, \text{cm}^3 \]
- **Object R**:
- Volume of 295.4 cc, fully immersed.
\[ \text{Immersed Volume (R)} = 295.4 \, \text{cm}^3 \]
- **Object S**:
- Volume of 397 cc, fully immersed.
\[ \text{Immersed Volume (S)} = 397 \, \text{cm}^3 \]
4. **Calculate Total Water Displacement**:
\[ \text{Total Displacement} = 57.6 + 50 + 295.4 + 397 = 800 \, \text{cm}^3 \]
5. **Initial Water Volume**:
- Assume initial water filled the container at the level of total displacement:
\[ \text{Initial Water Volume} = 800 \, \text{cm}^3 \]
6. **New Water Level**:
- With objects removed, only the initial water remains:
- Cross-section of the container = 40 cm x 20 cm = 800 cm2.
- New height = Volume / Area:
\[ \text{New Water Height} = \frac{800 \, \text{cm}^3}{800 \, \text{cm}^2} = 1 \, \text{cm} \]
Since 1 cm is not within the specified range (9,9), there might be a discrepancy in assumptions; however, based on calculations with the given inputs, the new water level is 1 cm.