In the circuit shown in the figure, the total charge is \( 750 \, \mu C \) and the voltage across capacitor \( C_2 \) is \( 20 \, {V} \). Then the charge on capacitor \( C_2 \) is:
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In a series circuit, the charge on all capacitors is the same. Use \( Q = C \times V \) to calculate the charge on each capacitor.
Step 1: In a series circuit, the total charge on all capacitors is the same. Therefore, the total charge is equal to the charge on each capacitor. Step 2: The charge \( Q \) on each capacitor in the series is given by: \[ Q = C_2 \times V_2, \] where \( V_2 = 20 \, {V} \) is the voltage across capacitor \( C_2 \). Step 3: The total charge is given as \( 750 \, \mu C \). From the equation above, we can find \( Q \) on \( C_2 \). \[ Q_2 = 590 \, \mu C. \]
