Question

In the circuit shown in the figure, the input voltage $V_i$ is $20V,V_{BE}=0$ and $V_{CE}=0$. The values of $I_B,I_C$ and $\beta$ are given by:

• (A) $I_B=20\mu A,I_C=5mA,\beta =250$
• (B) $I_B=40\mu A,I_C=10mA,\beta =250$
• (C) $I_B=40\mu A,I_C=5mA,\beta =125$
• (D) $I_B=25\mu A,I_C=5mA,\beta =200$

Answer 1

The Correct Option is C

Explanation:
Given,$V_i=V_{BE}+R_B{i}_B$....(1)$20=500\times {10}^3\times i_B$$i_B=40\mu A$$V_0=V_{CE}-R_C{i}_C$...(2)$20=4\times {10}^3{i}_C$$i_C=5mA$$\beta =\frac{I_C}{I_B}=\frac{5mA}{40\mu A}=125$Hence, the correct option is (C).