Question

In hydrogen atom, an electron is revolving in the orbit of radius 0.53 Å with \( 6.6 \times 10^{15} \) radiations. Magnetic field produced at the centre of the orbit is

• A. \( 0.125 \, \text{Wb/m}^2 \)
• B. \( 1.25 \, \text{Wb/m}^2 \)
• C. \( 12.5 \, \text{Wb/m}^2 \)
• D. \( 1.25 \, \text{Wb/m}^2 \)

Hint:

Use the formula for the magnetic field around a moving electron to calculate the magnetic field produced at the centre of an orbit.

Answer 1

The Correct Option is B

The magnetic field due to a moving electron is given by \( B = \frac{\mu_0 e v}{2 \pi r} \), where \( \mu_0 \) is the permeability of free space, \( e \) is the charge of the electron, \( v \) is the velocity, and \( r \) is the radius. Using the given values, we find the magnetic field produced.

Step 2: Conclusion.
The magnetic field produced at the centre of the orbit is \( 1.25 \, \text{Wb/m}^2 \), corresponding to option (b).