Question:

In $ HCO{{O}^{-}} $ , the two carbon-oxygen bonds are found to be of equal length. What is the reason for this?

Updated On: Apr 1, 2024
  • The anion is obtained by the removal of a proton from the acid molecule
  • Electronic orbitals of carbon atoms are hybridized
  • The $ C=O $ bond is weaker than $ C-O $ bond
  • The anion $ HCO{{O}^{-}} $ has two resonating Structures
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The Correct Option is D

Solution and Explanation

In $ HCO{{O}^{-}} $ , the two carbon oxygen bonds are of equal length because the anion HCOO has two resonating structures.
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Concepts Used:

Aldehydes, Ketones, and Carboxylic Acids

Aldehydes, Ketones, and Carboxylic Acids are carbonyl compounds that contain a carbon-oxygen double bond. These organic compounds are very important in the field of organic chemistry and also have many industrial applications.

Aldehydes:

Aldehydes are organic compounds that have the functional group -CHO.

Preparation of Aldehydes

Acid chlorides are reduced to aldehydes with hydrogen in the presence of palladium catalyst spread on barium sulfate.

Ketones:

Ketones are organic compounds that have the functional group C=O and the structure R-(C=O)-R’.

Preparation of Ketones

Acid chlorides on reaction with dialkyl cadmium produce ketones. Dialkyl cadmium themselves are prepared from Grignard reagents.

Carboxylic Acid:

Carboxylic acids are organic compounds that contain a (C=O)OH group attached to an R group (where R refers to the remaining part of the molecule).

Preparation of Carboxylic Acids

Primary alcohols are readily oxidized to carboxylic acids with common oxidizing agents such as potassium permanganate in neutral acidic or alkaline media or by potassium dichromate and chromium trioxide in acidic media.