To solve this problem, we need to understand how the transconductance \( g_m \) of a Field-Effect Transistor (FET) changes as the gate-source voltage \( V_{GS} \) is varied.
- Transconductance (\( g_m \)): In a Field-Effect Transistor (FET), the transconductance \( g_m \) is defined as the rate of change of the drain current \( I_D \) with respect to the gate-source voltage \( V_{GS} \), i.e.,
\[ g_m = \frac{\partial I_D}{\partial V_{GS}} \]
- The value of \( g_m \) depends on the operating region of the FET, particularly in relation to \( V_{GS} \). In an enhancement-mode FET, as \( V_{GS} \) increases, the channel becomes more conductive, and \( g_m \) typically increases as well.
- For \( V_{GS} = 0 \), the FET is typically in the off state, and the drain current \( I_D \) is zero, so the transconductance \( g_m \) is zero.
- As \( V_{GS} \) increases, the channel begins to conduct, and \( g_m \) increases because the drain current becomes more sensitive to changes in \( V_{GS} \).
- As the reverse bias \( V_{GS} \) continues to increase, \( g_m \) may initially increase but eventually saturates or decreases, depending on the type of FET and the voltage threshold.
As \( V_{GS} \) increases from zero to a reverse bias in FETs, the transconductance \( g_m \) typically decreases because the FET moves into the cutoff or sub-threshold region where the drain current becomes less sensitive to the gate voltage.