In borex bead test which compound is formed
- Ortho borate
- Meta borate
- Double oxide
- Tetra borate
The Correct Option is B
Solution and Explanation
The correct option is (B) : Meta borate
The blister test is another name for the borax bead test. It is the first test available to identify the presence of particular metals. Cobalt, copper, and nickelate salts are used to provide this test. This test identifies the presence of metals in a sample. Finding the metal ions in salt is done using a straightforward scientific procedure. Here, a little quantity of salt, borax, and a few molten beads on the end of a piece of platinum are combined. The reaction's byproducts are sodium metaborate and boric anhydride. The substance that is employed to find coloured radicals is borax bead.
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Statement II: Nitrogen does not form halides with +5 oxidation state due to the absence of d-orbital in it.
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
- P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.
P block elements consist of:
- Group 13 Elements: Boron family
- Group 14 Elements: Carbon family
- Group 15 Elements: Nitrogen family
- Group 16 Elements: Oxygen family
- Group 17 Elements: Fluorine family
- Group 18 Elements: Neon family