Question:
In borax bead test which compound is formed?
In borax bead test which compound is formed?
Updated On: Jul 12, 2022
- Ortho borate
- Meta borate
- Double oxide
- Tetra borate
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The Correct Option is B
Solution and Explanation
In borax bead test the coloured meta borates are
formed by transition metal salts.
$ Na_2B_4O_7 . \, 10H_2O \xrightarrow[-10H_2O] {\triangle} Na_2 B_4 O_7 $
$\hspace30mm$ $ \xrightarrow{\triangle} 2NaBO_2 + B_2O_3$
$ B_2O_3 + CuO \longrightarrow Cu(BO_2)_2 $
$\hspace30mm$ Cupric m etaborate
$\hspace30mm$ (Blue bead)
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
- P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.
P block elements consist of:
- Group 13 Elements: Boron family
- Group 14 Elements: Carbon family
- Group 15 Elements: Nitrogen family
- Group 16 Elements: Oxygen family
- Group 17 Elements: Fluorine family
- Group 18 Elements: Neon family