Question:
In an experiment, $4 \,g$ of $ M_{2}O_{x} $ oxide was reduced to $2.8 \,g$ of the metal. If the atomic mass of the metal is $ 56\,g\,mol^{-1}, $ the number of $O$ atoms in the oxide is
In an experiment, $4 \,g$ of $ M_{2}O_{x} $ oxide was reduced to $2.8 \,g$ of the metal. If the atomic mass of the metal is $ 56\,g\,mol^{-1}, $ the number of $O$ atoms in the oxide is
Updated On: Jun 23, 2023
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The Correct Option is C
Solution and Explanation
Mass of oxygen in oxide $=4-2.8$
$=1.2 \,g $
E wt. of metal $=\frac{\text { mass of metal }}{\text { mass of oxygen }} \times 8 $&
$=\frac{2.8}{1.2} \times 8 $
$=18.67$
Valency of metal $=\frac{\text { atomic wt. of metal }}{\text { e wt. of metal }}$
$=\frac{56}{18.67} $ (given)
$=3$
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Chemistry is a vast subject and for understanding its significance we can take help of following points:
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Classification of Matter
There are two ways of classifying the matter:
(A) Physical Classification:
Matter can exist in three physical states:
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