boys = 900
girls = 1100
Passed = 32% of 900 + 38% of 1100 = 288 + 418 = 706
Failed = 2000 - 706 = 1294
Total % of failed candidates
= \(\frac{(2000 - 706) }{ 2000} \)
\(= \frac{1294}{2000} \)
\(= 64.7%\)
Therefore, the correct option is (B): 64.7%
List-I | List-II |
---|---|
(A) Confidence level | (I) Percentage of all possible samples that can be expected to include the true population parameter |
(B) Significance level | (III) The probability of making a wrong decision when the null hypothesis is true |
(C) Confidence interval | (II) Range that could be expected to contain the population parameter of interest |
(D) Standard error | (IV) The standard deviation of the sampling distribution of a statistic |