The correct option is (B): 48
The problem requires selecting 5 questions from two groups of 4 questions each, with the restriction that not more than 3 questions can be selected from any group.
Step 1: Understand the possibilities
To satisfy the condition that no more than 3 questions can be selected from any group, the possible combinations of questions from Group 1 and Group 2 are:
- 3 questions from Group 1 and 2 questions from Group 2
- 2 questions from Group 1 and 3 questions from Group 2
Step 2: Calculate each case
1. Selecting 3 questions from Group 1 and 2 questions from Group 2:
The number of ways to choose 3 questions from 4 in Group 1 is \(C\binom{4}{3}\), and the number of ways to choose 2 questions from 4 in Group 2 is \(C\binom{4}{2}\).
So, the number of ways is:
\(C\binom{4}{3}\) \times \(C\binom{4}{2}\) = 4 \times 6 = 24\]
2. Selecting 2 questions from Group 1 and 3 questions from Group 2:
The number of ways to choose 2 questions from 4 in Group 1 is \( \binom{4}{2} \), and the number of ways to choose 3 questions from 4 in Group 2 is \( \binom{4}{3} \).
So, the number of ways is:
\[\binom{4}{2} \times \binom{4}{3} = 6 \times 4 = 24\]
Step 3: Total number of ways
The total number of ways to select the questions is:
\[24 + 24 = 48\]
Final Answer:
The number of ways to select 5 questions is 48.