Let the maximum marks be \(M\). The student failed by 10%, meaning the student got 90% of the marks required to pass.
The student got 225 marks, and needed 300 to pass. He was short 300 - 225 = 75 marks from passing, therefore, 225 = 300 - 75 marks
Thus the student was declared fail by 75/300 = 25%, instead of 10% as given. We proceed further with the given data: The student needed 300 marks to pass, hence the student achieved 300/M = 1 - 10/100 = 0.9, therefore passing mark percentage can be written as 300/M = 0.9, then
300 = 0.9 * M,
then \(M = \frac{300}{0.9} = \frac{3000}{9} = \frac{1000}{3} \approx 333 \)
This result differs from any options.
Since The student needed 300 marks to pass, the studnet scored 225 marks and was declared fail by 10%, hence this can be written as 225 = 90/100 * Maximum marks i.e. 225 = 0.9 \(\times\) M, hence
then \(M = \frac{225}{0.9} = \frac{2250}{9} = 250\)
This result also differs from any options.
Assuming he needs to pass 300 marks to pass after 225 achieved marks, means he needs 75 more marks, these 75 marks represent 10 % of max marks, hence
75 = 10/100 \(\times\) M M = 750
List-I | List-II |
---|---|
(A) Confidence level | (I) Percentage of all possible samples that can be expected to include the true population parameter |
(B) Significance level | (III) The probability of making a wrong decision when the null hypothesis is true |
(C) Confidence interval | (II) Range that could be expected to contain the population parameter of interest |
(D) Standard error | (IV) The standard deviation of the sampling distribution of a statistic |