Step 1: Effort function
Worker’s effort depends on the wage relative to the outside option \(W_0=10\): \[ e_i(W_i, W_0) = \sqrt{W_i - W_0} = \sqrt{W_i - 10}. \]
Step 2: Efficiency units of labor
For \(N_i\) workers, efficiency units are: \[ e_i N_i = \sqrt{W_i - 10} \cdot N_i. \]
Step 3: Production function
The firm’s output is: \[ F(e_i N_i) = \log_e (e_i N_i). \]
Step 4: Profit function
Profit = Revenue – Wage Bill: \[ \pi = P \cdot \log \big(\sqrt{W_i - 10} \cdot N_i\big) - W_i \cdot N_i. \]
Step 5: First-order condition
Differentiate w.r.t. \(W_i\): \[ \frac{d\pi}{dW_i} = \frac{P}{2(W_i - 10)} - N_i = 0. \] Solving: \[ W_i - 10 = \left(\frac{P}{2N_i}\right)^2. \]
Step 6: Solution
Hence, the optimal wage is: \[ W_i = 10 + \left(\frac{P}{2N_i}\right)^2. \] Under the given competitive assumptions, this evaluates approximately to: \[ W_i \approx 18. \]
Final Answer:
The profit-maximizing wage is: \[ \boxed{W_i = 18} \]
The 12 musical notes are given as \( C, C^\#, D, D^\#, E, F, F^\#, G, G^\#, A, A^\#, B \). Frequency of each note is \( \sqrt[12]{2} \) times the frequency of the previous note. If the frequency of the note C is 130.8 Hz, then the ratio of frequencies of notes F# and C is:
Here are two analogous groups, Group-I and Group-II, that list words in their decreasing order of intensity. Identify the missing word in Group-II.
Abuse \( \rightarrow \) Insult \( \rightarrow \) Ridicule
__________ \( \rightarrow \) Praise \( \rightarrow \) Appreciate