In a Vernier caliper, \(N+1\) divisions of vernier scale coincide with \(N\) divisions of main scale. If 1 MSD represents 0.1 mm, the vernier constant (in cm) is:
Calculating the Vernier Constant (V.C.)
Step 1: Formula for the Vernier Constant (V.C.)
The Vernier constant is given by:
V.C. = Value of 1 MSD − Value of 1 VSD
Step 2: Relate MSD and VSD values
If (N + 1) VSDs coincide with N MSDs, then:
Value of 1 VSD = Value of 1 MSD × (N / (N + 1))
Step 3: Substitute Values and Simplify
Now substitute the values:
V.C. = 0.1mm − 0.1mm × (N / (N + 1))
V.C. = 0.1 / (N + 1) mm
Quick Tip
To convert to centimeters, use:
V.C. = 1 / 100(N + 1) cm
The Vernier constant is given by:
V.C. = Value of 1 MSD − Value of 1 VSD
If (N + 1) VSDs coincide with N MSDs, then:
Value of 1 VSD = Value of 1 MSD × (N / (N + 1))
Now substitute the values:
V.C. = 0.1mm − 0.1mm × (N / (N + 1))
V.C. = 0.1 / (N + 1) mm
To convert to centimeters, use:
V.C. = 1 / 100(N + 1) cm
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A : The potential (V) at any axial point, at 2 m distance(r) from the centre of the dipole of dipole moment vector
\(\vec{P}\) of magnitude, 4 × 10-6 C m, is ± 9 × 103 V.
(Take \(\frac{1}{4\pi\epsilon_0}=9\times10^9\) SI units)
Reason R : \(V=±\frac{2P}{4\pi \epsilon_0r^2}\), where r is the distance of any axial point, situated at 2 m from the centre of the dipole.
In the light of the above statements, choose the correct answer from the options given below :
The output (Y) of the given logic gate is similar to the output of an/a :