Question

 In a simultaneous throw of a pair of dice, find the probability of getting a total of 9 or more.

• A. \(\frac{5}{18}\)
• B. \(\frac{2}{36}\)
• C. \(\frac{5}{12}\)
• D. \(\frac{2}{7}\)

Answer 1

The Correct Option is A

To find the probability of getting a total of 9 or more when a pair of dice is thrown simultaneously, we need to determine the total number of favorable outcomes and divide it by the total number of possible outcomes.

Step 1: Calculate the total number of possible outcomes.

The total number of possible outcomes when two dice are thrown is \(6 \times 6 = 36\), because each die has 6 faces.

Step 2: Determine the favorable outcomes for a sum of 9 or more.

Now, let's find the combinations of dice faces that sum to 9 or more:

• Sum = 9: (3,6), (4,5), (5,4), (6,3)
• Sum = 10: (4,6), (5,5), (6,4)
• Sum = 11: (5,6), (6,5)
• Sum = 12: (6,6)

This gives us a total of 10 favorable outcomes.

Step 3: Calculate the probability.

The probability of getting a total of 9 or more is the number of favorable outcomes divided by the total possible outcomes:

\(\frac{10}{36} = \frac{5}{18}\)

Conclusion:

The probability of getting a total of 9 or more when a pair of dice is thrown is \(\frac{5}{18}\).

Correct Answer: \(\frac{5}{18}\)