Question:

In a series LCR circuit, if the current leads the source voltage, then:

Show Hint

In a series LCR circuit, the circuit is capacitive when \( X_C>X_L \), causing the current to lead the voltage.
Updated On: Mar 11, 2025
  • \( X_C>X_L \)
  • \( X_L>X_C \)
  • \( X_L = X_C \neq 0 \)
  • \( X_L = X_C = 0 \)
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

In an LCR circuit, the phase relationship between voltage and current depends on the reactances: \[ X_L = \omega L, \quad X_C = \frac{1}{\omega C} \] The phase angle \( \phi \) is given by: \[ \tan \phi = \frac{X_L - X_C}{R} \] If the current leads the voltage, the circuit behaves like a capacitive circuit, meaning: \[ X_C>X_L \]
Was this answer helpful?
0
0

Top Questions on Current electricity

View More Questions