The correct option is (A): 1.05 cm
Explanation:
Let the depth of first resonance of the pipe be l1 = 22.7 cm
Let the depth of second resonance of the pipe be l2 = 70.2 cm
For the end correction,
\(\rightarrow \frac{l_{2}+x}{l_{1}+x}=\frac{3\frac{\pi}{4}}{\frac{\pi}{4}}\)
\(\rightarrow \frac{l_{2}+x}{l_{1}+x}=3\)
\(\rightarrow x=\frac{l_{2}-3l_{1}}{2}\)
After substituting the values, we get:
\(\rightarrow x=\frac{70.2−3 \times 22.7}{2}\)
\(\rightarrow x=\frac{70.2−68.1}{2}\)
\(\rightarrow x=\frac{2.1}{2}\)
\(\rightarrow x=1.05\text{ cm}\)
Therefore, the end correction is 1.05 cm.
Sound is a vibration that propagates the mechanical wave of displacement and pressure, through a medium can be of any matter. In other words, the sound is the thin line between Music sound and Noise.
Sound can be divided into two types depending on its frequency. The following are:-