Question

In a randomly mating population, the frequency of 'A' allele is 0.7. What is the frequency of An" genotype in the next generation according to Hardy- Weinberg's law? (up to two decimal places)

Answer 1

Correct Answer: 0.41

To solve this problem using the Hardy-Weinberg principle, we first need to understand the terms involved. Hardy-Weinberg equilibrium states that in a large, randomly mating population, allele and genotype frequencies will remain constant from generation to generation in the absence of evolutionary influences.

We are given the frequency of the 'A' allele (p) as 0.7. The frequency of the 'a' allele (q) can be found using the equation p + q = 1. Therefore:
q = 1 - 0.7 = 0.3

According to Hardy-Weinberg's law, the genotype frequencies in the next generation are given by the formulas:

- AA genotype frequency (p²) = p² = (0.7)² = 0.49
- Aa genotype frequency (2pq) = 2pq = 2(0.7)(0.3) = 0.42
- aa genotype frequency (q²) = q² = (0.3)² = 0.09

Based on the calculations under standard Hardy-Weinberg conditions, the frequency of the Aa genotype is 0.42.