In a monohybrid cross between two heterozygous pea plants (Pp x Pp), the alleles segregate according to Mendelian inheritance. The possible genotypes of the offspring are:
- PP (homozygous dominant),
- Pp (heterozygous),
- pp (homozygous recessive).
By using a Punnett square, we can determine the genotypic and phenotypic ratios.
- The possible genotypes are:
- 1 PP : 2 Pp : 1 pp.
Since P (dominant) is responsible for the dominant phenotype and p (recessive) is responsible for the recessive phenotype, the phenotypic ratio is:
- 3 dominant (PP and Pp) : 1 recessive (pp).
Thus, the expected phenotypic ratio of the offspring is 3:1.