Question:

In a Millikan’s oil drop experiment, the charge on an oil drop is calculated to be \( 6.35 \times 10^{-19} \, \text{C} \). The number of excess electrons on the drop is:

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The number of excess electrons on an oil drop is calculated by dividing the total charge by the charge of a single electron.
Updated On: Jan 6, 2026
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The Correct Option is C

Solution and Explanation

Step 1: Formula for number of excess electrons.
The number of excess electrons is given by: \[ n = \frac{q}{e} \] where \( q \) is the total charge and \( e \) is the charge of an electron.
Step 2: Calculation.
Substituting the given charge of the drop and the charge of an electron: \[ n = \frac{6.35 \times 10^{-19}}{1.6 \times 10^{-19}} = 6 \]
Final Answer: \[ \boxed{6} \]
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