Question

In a hotel, 60% had vegetarian lunch, 30% had non-vegetarian lunch and 15% had both types. If 96 people were present, how many did not eat either type of lunch?

• A. 20
• B. 24
• C. 26
• D. 28

Hint:

Use the formula: \( A + B - Both \) to find total who had at least one, then subtract from total.

Answer 1

The Correct Option is B

People who had either veg or non-veg or both = \( 60 + 30 - 15 = 75% \)
Hence, those who did not eat either = \( 100 - 75 = 25% \)
\[ 25% \text{ of } 96 = \frac{25}{100} \times 96 = 24 \]