Question:
In a chemostat with dilution rate 0.8 h\(^{-1}\), biomass concentration = 8 mol m\(^{-3}\), and specific product formation rate = 0.2 (mol product)(mol biomass)\(^{-1}\) h\(^{-1}\), the steady-state product concentration (mol m\(^{-3}\)) is \(\underline{\hspace{1cm}}\).
In a chemostat with dilution rate 0.8 h\(^{-1}\), biomass concentration = 8 mol m\(^{-3}\), and specific product formation rate = 0.2 (mol product)(mol biomass)\(^{-1}\) h\(^{-1}\), the steady-state product concentration (mol m\(^{-3}\)) is \(\underline{\hspace{1cm}}\).
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In chemostat steady state, product concentration depends on biomass, production rate, and dilution rate.
Updated On: Jan 2, 2026
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Correct Answer: 2
Solution and Explanation
Steady-state product concentration is given by:
\[ P = \frac{q_p X}{D} \]
Substituting values:
\[ P = \frac{0.2 \times 8}{0.8} = \frac{1.6}{0.8} = 2 \]
\[ P = \frac{q_p X}{D} \]
Substituting values:
\[ P = \frac{0.2 \times 8}{0.8} = \frac{1.6}{0.8} = 2 \]
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