Question:
In a Carnot engine, if the temperatures of the source and sink are both decreased by 100 K, the efficiency:
In a Carnot engine, if the temperatures of the source and sink are both decreased by 100 K, the efficiency:
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Carnot efficiency depends on temperature ratio. Decreasing both lowers the ratio, increasing efficiency.
Updated On: May 13, 2025
- increases
- decreases
- remains constant
- becomes one
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The Correct Option is A
Solution and Explanation
Efficiency of Carnot engine: \( \eta = 1 - \frac{T_c}{T_h} \). If both \( T_c \) and \( T_h \) decrease by same value, ratio \( \frac{T_c}{T_h} \) reduces → efficiency increases.
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