Question:

Imagine a new planet having the same density as that of earth but it is 3 times bigger than the earth in size. If the acceleration due to gravity on the surface of earth is g and that on the surface of the new planet is g', then :

Updated On: Oct 20, 2023
  • g'=3g

  • g'=\(\frac{g}{9}\)

  • g'=9g

  • g'=\(\frac{g}{3}\)

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The Correct Option is A

Solution and Explanation

Let the mass and radius of the new planet be M′ and R′, then for same density as earth,
R′=3R
M′=27M
we know M\(\propto\)V, where V\(\propto\)R3
For Earth 

g=\(\frac{GM}{R^2}\)  (1)

and for new planet

g'=\(\frac{GM'}{R^2}\)

=\(\frac{G(27M)}{(3R)^2}\)

=\(3\bigg(\frac{GM}{R^2}\bigg)\)=3g

\(\Rightarrow\) g'=3g

Therefore, the correct option is (A): g'=3g

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Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].