Question

If \(y=x^{x^x}\), then y' =

• A. \(\frac{-y^2}{x(1-y\log x)}\)
• B. \(\frac{y^2}{1-y\log x}\)
• C. \(\frac{y^2}{x(1-y\log x)}\)
• D. \(\frac{-y^2}{1-y\log x}\)

Answer 1

The Correct Option is C

The correct option is (C) : \(\frac{y^2}{x(1-y\log x)}\).