Question:
If \(y=x^{x^x}\), then y' =
If \(y=x^{x^x}\), then y' =
Updated On: Sep 15, 2024
- \(\frac{-y^2}{x(1-y\log x)}\)
- \(\frac{y^2}{1-y\log x}\)
- \(\frac{y^2}{x(1-y\log x)}\)
- \(\frac{-y^2}{1-y\log x}\)
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The Correct Option is C
Solution and Explanation
The correct option is (C) : \(\frac{y^2}{x(1-y\log x)}\).
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