Step 1: Identify \(n\).
Since range is \(\{0,1,2,3,4,5,6\}\),
\[ n=6 \]
Step 2: Write probability expressions.
\[ P(X=2)=\binom{6}{2}p^2(1-p)^4 \]
\[ P(X=4)=\binom{6}{4}p^4(1-p)^2 \]
Step 3: Use given relation.
\[ \binom{6}{2}p^2(1-p)^4 = 4\binom{6}{4}p^4(1-p)^2 \]
Step 4: Simplify.
\[ 15p^2(1-p)^4 = 4\cdot 15p^4(1-p)^2 \]
Cancel \(15p^2(1-p)^2\):
\[ (1-p)^2 = 4p^2 \]
Take positive root (since \(p>0\)):
\[ 1-p = 2p \Rightarrow 1=3p \Rightarrow p=\frac{1}{3} \]
Final Answer:
\[ \boxed{\frac{1}{3}} \]
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If the probability distribution is given by:
| X | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
|---|---|---|---|---|---|---|---|---|
| P(x) | 0 | k | 2k | 2k | 3k | k² | 2k² | 7k² + k |
Then find: \( P(3 < x \leq 6) \)
If \(S=\{1,2,....,50\}\), two numbers \(\alpha\) and \(\beta\) are selected at random find the probability that product is divisible by 3 :