We are given: \( x + \frac{1}{x} = 2 \).
Let us assume \( x = 1 \). Then, \( x + \frac{1}{x} = 1 + 1 = 2 \) which satisfies the condition.
Now we compute \( x^{17} + \frac{1}{x^{17}} \).
Since \( x = 1 \), we have \( x^{17} + \frac{1}{x^{17}} = 1 + 1 = 2 \).