Question

if \(x=\frac{3at}{(a+t^3)},y=\frac{3at^2}{(1+t^3)}, then \frac{dy}{dx }at \,\,t=\frac{1}{2}\) is

• A. \(\frac{4}{3}\)
• B. \(\frac{17}{12}\)
• C. \(\frac{19}{15}\)
• D. \(\frac{5}{4}\)

Answer 1

The Correct Option is B

The correct option is (B): \(\frac{17}{12}\)