if \(x=\frac{3at}{(a+t^3)},y=\frac{3at^2}{(1+t^3)}, then \frac{dy}{dx }at \,\,t=\frac{1}{2}\) is
- \(\frac{4}{3}\)
- \(\frac{17}{12}\)
- \(\frac{19}{15}\)
- \(\frac{5}{4}\)
The Correct Option is B
Solution and Explanation
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