Question:

If $v_e$ is escape velocity and $v _o$ is orbital velocity of a satellite for orbit close to the earth's suface, then these are related by

Updated On: May 25, 2022
  • $v_o = \sqrt 2v_e$
  • $v_o = v_e$
  • $v_e = \sqrt 2v_o$
  • $v_e = \sqrt 2$
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The Correct Option is C

Solution and Explanation

Escape velocity, $v_e = \sqrt \frac {2GM}{R} \, \, \, \, \, \, ...(i)$
where M and R be the mass and radius of the earth respectively.
The orbital velocity of a satellite close to the earth's surface is
$v_o = \sqrt \frac {GM}{R} \, \, \, \, \, \, \, \, \, \, ...(ii)$
From (i) and (ii), we get
$v_e = \sqrt {2v_o}$
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Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].