U = {1, 2, 3, 4, 5, 6, 7, 8, 9}
A = {2, 4, 6, 8}, B = {2, 3, 5, 7}
(i) (\(A ∪ B)' =\) {2,3,4,5,6,7,8}' = {1,9}
\(A' ∩ B' =\) {1,3,5,7,9} \(\cap\) (1,4,6,8,9) = {1,9}
\(∴ (A ∪ B)' = A' ∩ B'\)
(ii) \((A ∩ B)' =\) {2}\('\) = {1,3,4,5,6,7,8,9}
\(A' ∪ B' =\) {1,3,5,7,9} \(\cup\) {1,4,6,8,9} = {1,3,4,5,6,7,8,9}
\(∴ (A ∩ B)' = A' ∪ B' \)
Figures 9.20(a) and (b) refer to the steady flow of a (non-viscous) liquid. Which of the two figures is incorrect ? Why ?
The complement of a set is described as A’ = {x: x ∈ U and x ∉ A}
where,
A’ stands for the complement.
1. Complement Laws: The union of a set A and its complement A’ allows the universal set U of which, A and A’ are a subset.
A ∪ A’ = U
Also, the intersection of a set A and its complement A’ cause the empty set ∅.
A ∩ A’ = ∅
For Example: If U = {11, 12 , 13 , 14 , 15 } and A = {11 , 12 , 13 } then A’ = {14 , 15}. From this it can be seen that
A ∪ A’ = U = { 11 , 12 , 13 , 14 , 15}
Also, A ∩ A’ = ∅
2. Law of Double Complementation: According to the law, if we take the complement of the complemented set A’ then, we get the set A itself.
(A’)’ = A
In the previous example we can see that, if U = {11 , 12 , 13 , 14 , 15} and A = {11 , 12, 13} then A’ ={14 , 15}. Now if we consider the complement of set ‘A’ we get,
(A’)’ = {11 , 12 , 13} = A
This gives back the set A itself.
3. Law of empty set and universal set: According to this law the complement of the universal set gives us the empty set and vice-versa i.e.,
∅’ = U And U’ = ∅
This law is accessible.