Question:

If two events A and B. If odds against A are 2:1 and those in favour of \( A \cup B \) are 3:1, then

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To find the probability of events in combination, use the relationship \( P(A \cup B) = P(A) + P(B) - P(A \cap B) \).
Updated On: Jan 6, 2026
  • \( \frac{1}{2} \leq P(B) \leq \frac{3}{4} \)
  • \( \frac{5}{12} \leq P(B) \leq \frac{3}{4} \)
  • \( \frac{1}{5} \leq P(B) \leq \frac{3}{4} \)
  • None of these
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The Correct Option is B

Solution and Explanation


Step 1: Using probability relations.
The odds against \( A \) give \( P(A) = \frac{1}{3} \), and the odds in favor of \( A \cup B \) give \( P(A \cup B) = \frac{3}{4} \). By using these values, we can solve for the range of \( P(B) \).

Step 2: Conclusion.
The probability \( P(B) \) lies between \( \frac{5}{12} \) and \( \frac{3}{4} \), corresponding to option (2).
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