Question:
If the supply of oxygen is limited, $ H_{2}S $ reacts with $ O_{2} $ to form
If the supply of oxygen is limited, $ H_{2}S $ reacts with $ O_{2} $ to form
Updated On: Jul 2, 2022
- $ H_{2}O+SO_{3} $
- $ H_{2}O+S $
- $ H_{2}SO_{4}+S $
- $ H_{2}O+SO_{2} $
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The Correct Option is B
Solution and Explanation
In limited supply of oxygen, $H _{2} S$ burns with blue flame and $S$ and $H _{2} O$ are the main products.
$2 H _{2} S + O _{2} \longrightarrow 2 H _{2} O +2 S$
In excess of oxygen, $H _{2} S$ gives $SO _{2}$ and water as main product.
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
- P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.
P block elements consist of:
- Group 13 Elements: Boron family
- Group 14 Elements: Carbon family
- Group 15 Elements: Nitrogen family
- Group 16 Elements: Oxygen family
- Group 17 Elements: Fluorine family
- Group 18 Elements: Neon family