Question

If the specific heat capacity (\(c_p\)) of solids in potato is 837.36 J kg⁻¹ K⁻¹, then the specific heat capacity of potatoes in J kg⁻¹ K⁻¹ with 85% moisture content (wet basis) is _____. \(\textit{[Round off to two decimal places]}\)

Hint:

When calculating the specific heat capacity of a substance with moisture content, multiply the specific heat of the dry substance by the fraction of the dry matter in the substance.

Answer 1

Correct Answer: 3678

The specific heat capacity of potatoes with moisture content can be calculated using the formula: \[ c_p' = c_p \times (1 - X_{\text{wet}}) \] where:
- \( c_p = 837.36 \, \text{J/kg} \, \text{K} \),
- \( X_{\text{wet}} = 0.85 \) (moisture content on the wet basis).
Substitute the given values into the formula: \[ c_p' = 837.36 \times (1 - 0.85) = 837.36 \times 0.15 = 125.60 \, \text{J/kg} \, \text{K}. \] Thus, the specific heat capacity is approximately \( \boxed{125.60} \, \text{J/kg} \, \text{K} \) (rounded to two decimal places).