Question:

If the ratio of the roots of the equation px2+qx+r=0 is 1 : a, then which of the following relations is/are correct?

  • a+1)2a=a2pr\frac{a+1)^2}{a}=\frac{a^2}{pr}
  • (a+12a)=a2pr(\frac{a+1^2}{a})=\frac{a^2}{pr}
  • a+1a+2=q2pra+\frac{1}{a}+2=\frac{q^2}{pr}
  • (a+1q)2=apr(\frac{a+1}{q})^2=\frac{a}{pr}
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The Correct Option is A, C, D

Solution and Explanation

The correct option is: A, C and D
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