If the ratio of the linear densities (denier) of two circular fibers is 3, the corresponding ratio of their diameters, (rounded off to two decimal places), is \(\underline{\hspace{2cm}}\).
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For fibers, the ratio of linear densities is proportional to the square of the ratio of their diameters.
The linear density of a fiber is proportional to the square of its diameter. Therefore, if the ratio of the linear densities is 3, the ratio of the diameters \( D_1 \) and \( D_2 \) is given by:
\[
\frac{D_1}{D_2} = \sqrt{3} \approx 1.732.
\]
Thus, the ratio of the diameters is \( 1.73 \).
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