To solve the problem, we'll use the given information about the ratios between the numbers. Let's define the numbers:
- The ratio between the first number and the second number is \(2:3\). Assume the first number is \(2x\) and the second number is \(3x\).
- The ratio between the second number and the third number is \(5:3\). Use \(3x\) for the second number and assume the third number is \(3y\), so we have \(\frac{3x}{3y}=\frac{5}{3}\).
- From \(\frac{3x}{3y}=\frac{5}{3}\), solve for \(x\) in terms of \(y\):
\[3x=5 \cdot 3y\]
\[3x=15y\]
\[x=5y\]
- Substitute \(x=5y\) back into the expression for the first number, \(2x\):
\[2x=2 \cdot 5y=10y\]
- Given that \(10y\) is the expression for the first number, match against the options provided. According to the answer given (6), \(10y=6\):
\[10y=6\]
\[y=\frac{6}{10}=0.6\]
Substitute \(y\) back to find \(x\):
\[x=5 \cdot 0.6=3\]
- The first number \(2x=2 \cdot 3=6\).