In a rhombus, the diagonals bisect each other at right angles. Therefore, the diagonals divide the rhombus into four right-angled triangles. The half-lengths of the diagonals form the two perpendicular sides of a right-angled triangle, and the side of the rhombus is the hypotenuse. Given:
One diagonal is 30 cm, so half of it is \( \frac{30}{2} = 15 \) cm.
The other diagonal is 40 cm, so half of it is \( \frac{40}{2} = 20 \) cm. Now, using the Pythagorean theorem to find the side \( s \) of the rhombus: \[ s^2 = 15^2 + 20^2 \] \[ s^2 = 225 + 400 = 625 \] \[ s = \sqrt{625} = 25 \, \text{cm} \]
The correct option is (C): \(25\ cm\)
List - I | List -II |
(Solids) | (Their Features) |
(A) Prism | (I) Base is a circle. |
(B) Pyramid | (II) Two similar ends and rectangular faces. |
(C) Cone | (III) Two circular faces and one curved surface. |
(D) Cylinder | (IV) One base and slant triangular faces. |