-450
From the exponential term \( e^{i(\omega t + ax - 600y)} \), the wave vector \( \mathbf{k} \) is: \[ \mathbf{k} = a\hat{x} - 600\hat{y}. \] The direction of propagation of the electromagnetic wave is given by the wave vector \( \mathbf{k} \), and it must be perpendicular to the direction of the electric field \( \mathbf{E} \) because \( \mathbf{E} \cdot \mathbf{k} = 0 \) (transverse wave condition).
The electric field is: \[ \mathbf{E} = 4\hat{x} + 3\hat{y}. \] The dot product \( \mathbf{E} \cdot \mathbf{k} = 0 \) gives: \[ (4)(a) + (3)(-600) = 0. \] Simplify: \[ 4a - 1800 = 0. \] Solve for \( a \): \[ a = \frac{1800}{4} = 450. \]
The value of \( a \) is: 450.
The P-V diagram of an engine is shown in the figure below. The temperatures at points 1, 2, 3 and 4 are T1, T2, T3 and T4, respectively. 1β2 and 3β4 are adiabatic processes, and 2β3 and 4β1 are isochoric processes
Identify the correct statement(s).
[Ξ³ is the ratio of specific heats Cp (at constant P) and Cv (at constant V)]