Question:

If the electric current in a lamp decreases by $5 \%,$ then the power output decreases by

Updated On: Apr 30, 2024
  • 2.5 $\% $
  • 10 $\% $
  • 5 $\% $
  • 20 $\% $
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The Correct Option is B

Solution and Explanation

Power of lamp
$\hspace15mm P=i^2R $
or $\hspace15mm \frac {dP}{P}=2 \frac {? i}{i}= 2 \times 5 \% \hspace5mm \bigg (\because \frac {? i}{i}=5 \% \bigg ) $
$\hspace15mm =10 \% \$ decrease
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Concepts Used:

Electromagnetic Induction

Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-

  1. When we place the conductor in a changing magnetic field.
  2. When the conductor constantly moves in a stationary field.

Formula:

The electromagnetic induction is mathematically represented as:-

e=N × d∅.dt

Where

  • e = induced voltage
  • N = number of turns in the coil
  • Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
  • t = time

Applications of Electromagnetic Induction

  1. Electromagnetic induction in AC generator
  2. Electrical Transformers
  3. Magnetic Flow Meter