Question

If the displacement of a body moving on a horizontal surface is 151.25 cm in a time interval of 2.25 s, then the velocity of the body in the correct number of significant figures in cm s\(^{-1}\) is:

• A. 6722
• B. 67.22
• C. 67.222
• D. 0.672
• E. 67.2

Hint:

Always round your final result to match the least number of significant figures from the given data.

Answer 1

Answer: (E)

To determine the velocity, we use the basic formula: \[ v = \frac{d}{t} \] Given that \( d = 151.25 \) cm and \( t = 2.25 \) s, we compute: \[ v = \frac{151.25}{2.25} \approx 67.2222 { cm/s} \] Since the input values have three significant figures (the limiting value being 2.25 with three significant figures), we round the result to three significant figures: \[ v \approx 67.2 { cm/s} \]