If the coefficient of variation and mean of a frequency distribution are 5% and 125 respectively, then the standard deviation is:
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Remember: Coefficient of Variation (CV) is the ratio of the standard deviation to the mean, expressed as a percentage. Always convert percentage to decimal before calculation.
We are given:
Coefficient of Variation (CV) = $5%$ = $5/100 = 0.05$
Mean $(\barx) = 125$
Formula for coefficient of variation:
\[
CV = \frac\sigma\barx
\]
where $\sigma$ = standard deviation.
Substituting the given values:
\[
0.05 = \frac\sigma125
\]
Multiplying both sides by $125$:
\[
\sigma = 0.05 \times 125
\]
\[
\sigma = 6.25
\]
Thus, the standard deviation is $\mathbf6.25$.