Step 1: Recall the formula for the circumference of a circle.
The circumference of a circle is given by:
\[ C = 2\pi r, \]
where \( r \) is the radius of the circle. Substituting \( C = 22 \):
\[ 2\pi r = 22. \]
Solve for \( r \):
\[ r = \frac{22}{2\pi}. \]
Using \( \pi = \frac{22}{7} \):
\[ r = \frac{22}{2 \cdot \frac{22}{7}} = \frac{22 \cdot 7}{44} = \frac{7}{2} = 3.5 \, \text{cm}. \]
Step 2: Find the area of the circle.
The area of a circle is given by:
\[ A = \pi r^2. \]
Substitute \( r = 3.5 \):
\[ A = \pi (3.5)^2 = \pi \cdot 12.25. \]
Using \( \pi = \frac{22}{7} \):
\[ A = \frac{22}{7} \cdot 12.25 = 22 \cdot 1.75 = 38.5 \, \text{sq. cm}. \]
Step 3: Find the area of a quadrant.
A quadrant is one-fourth of the circle's area:
\[ \text{Area of quadrant} = \frac{1}{4} \cdot A = \frac{1}{4} \cdot 38.5 = 9.625 \, \text{sq. cm}. \]
Final Answer: The area of the quadrant is \( \mathbf{9.625 \, \text{sq. cm}} \), which corresponds to option \( \mathbf{(2)} \).
Length of an arc of a sector of angle 45° when the radius of the circle is 3 cm, is: