If the average solar radiation received by the earth is 500 W/m$^2$ and reflects 70 W/m$^2$, what is the available energy for absorption and heating the surface?
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Energy absorbed by a surface = Total incoming energy - Energy reflected by the surface.
The fraction of energy reflected is related to the surface's albedo.
In this case: Absorbed Energy = $500 \text{ W/m}^2 - 70 \text{ W/m}^2 = 430 \text{ W/m}^2$.
This absorbed energy is what causes the surface to heat up.
The interaction of solar radiation with the Earth's surface involves several processes:
Incoming Solar Radiation (Insolation): The total amount of solar energy received by the surface.
Reflection (Albedo): A portion of the incoming solar radiation is reflected back to space by the surface. The reflectivity of a surface is called its albedo.
Absorption: The portion of the incoming solar radiation that is not reflected is absorbed by the surface. This absorbed energy heats the surface.
Transmission (less relevant for opaque surfaces like land): Some radiation might pass through transparent or translucent materials.
The energy available for absorption and heating the surface is the incoming solar radiation minus the reflected solar radiation. Given: Average solar radiation received (Incoming) = 500 W/m$^2$ Reflected solar radiation = 70 W/m$^2$ Available energy for absorption and heating = Incoming Radiation - Reflected Radiation Available energy = 500 W/m$^2$ - 70 W/m$^2$ Available energy = 430 W/m$^2$ Option (a) is the total incoming radiation. Option (b) is the reflected radiation. Option (d) is the sum of incoming and reflected, which is incorrect. \[ \boxed{\text{430 W/m}^2} \]
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