Step 1: Analyze statement (1).
Statement (1) tells us that each diagonal of rectangle \( Q \) has length 10. The formula for the diagonal \( d \) of a rectangle with length \( l \) and width \( w \) is:
\[
d = \sqrt{l^2 + w^2}
\]
Since the diagonal is 10, we have:
\[
10 = \sqrt{l^2 + w^2} \quad \implies \quad 100 = l^2 + w^2
\]
This equation alone does not give us enough information to find the perimeter \( p = 2l + 2w \), so statement (1) alone is not sufficient.
Step 2: Analyze statement (2).
Statement (2) tells us that the area of rectangle \( Q \) is 48. The area \( A \) of a rectangle is given by:
\[
A = l \times w
\]
So:
\[
l \times w = 48
\]
This equation alone does not give us enough information to find the perimeter \( p = 2l + 2w \), so statement (2) alone is not sufficient.
Step 3: Combine both statements.
We now have two equations:
1. \( l^2 + w^2 = 100 \) (from statement (1))
2. \( l \times w = 48 \) (from statement (2))
We can solve this system of equations. Let’s use the identity:
\[
(l + w)^2 = l^2 + 2lw + w^2
\]
Substituting the known values:
\[
(l + w)^2 = 100 + 2 \times 48 = 100 + 96 = 196 \quad \implies \quad l + w = \sqrt{196} = 14
\]
Thus, the perimeter is:
\[
p = 2l + 2w = 2 \times 14 = 28
\]
\[
\boxed{28}
\]