Question:

If \( P \) is a double ordinate of hyperbola \[ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \] such that \( OPQ \) is an equilateral triangle, \( O \) being the centre of the hyperbola, then the eccentricity \( e \) of the hyperbola satisfies

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For hyperbolas with double ordinates, use the properties of the eccentricity and the geometry of the curve to solve for the required values.
Updated On: Jan 6, 2026
  • \( 1<e<\frac{2}{\sqrt{3}} \)
  • \( e = \frac{2}{\sqrt{3}} \)
  • \( e = \frac{\sqrt{3}}{2} \)
  • \( e>\frac{2}{\sqrt{3}} \)
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The Correct Option is A

Solution and Explanation


Step 1: Using properties of hyperbolas.
For a double ordinate of a hyperbola and an equilateral triangle formed with the center of the hyperbola, the eccentricity satisfies the condition \( 1<e<\frac{2}{\sqrt{3}} \).

Step 2: Conclusion.
The correct range for the eccentricity is \( 1<e<\frac{2}{\sqrt{3}} \), corresponding to option (1).
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