Question:

If \(P(A)=\dfrac{7}{11},\ P(B)=\dfrac{9}{11},\ P(A\cap B)=\dfrac{4}{11}\), then \(P(A/B)=\) ?

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"Given \(B\)" means reduce the sample space to \(B\): probability becomes \(P(\text{both})/P(B)\).
  • \(\dfrac{7}{9}\)
  • \(\dfrac{4}{9}\)
  • \(1\)
  • \(\dfrac{13}{22}\)
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The Correct Option is B

Solution and Explanation

Why use conditional formula: By definition, \[ P(A\mid B)=\frac{P(A\cap B)}{P(B)}. \] Substitute values: \[ P(A\mid B)=\frac{\tfrac{4}{11}}{\tfrac{9}{11}}=\frac{4}{11}\cdot\frac{11}{9}=\frac{4}{9}. \] So, given that \(B\) has occurred, the chance that \(A\) also occurs is \(\dfrac{4}{9}\).
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